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For a chemical reaction aArarr bB, log...

For a chemical reaction `aArarr bB`,
`log[-(d(A))/(dt)]=log[(d[B])/(dt)]+0.3`
Then find the approximately ratio of `a` and `b` is.

Text Solution

Verified by Experts

The correct Answer is:
2
`-1/a(d[A])/(dt)=1/b(d[B])/(dt)`
or `-(d[A])/(dt)=a/b(d[B])/(dt)`
or `log[-(d[A])/(dt)]=loga/b+"log"a/b+"log"(d[B])/(dt)`
`:. "log"a/b=0.3 implies a/b=2`
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