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A drop of solution ("volume" =0.05 mL) c...

A drop of solution `("volume" =0.05 mL)` contains `3xx10^(-2)` mole of `H^(+)`. If the rate constant of disappearance of `H^(+)` is `1.0xx10^(2) mol litre^(-1) minute^(-1)`. How long (in minutes) will it take to disappear all the `H^(+)` ions?

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The correct Answer is:
6
`0.05 mL` has `3xx10^(-2)` mole of `H^(+)`
`1000 mL` has `(3xx10^(-2)xx1000)/(0.05)=600` mole `H^(+)`
`K=X/t` (zero order, follow unit of K)
`t=600/(1xx10^(2))=6 minute`
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