Show that the time `t_(1//2)//t_(3//4)` for `n^(th)` order reaction is a function of 'n' alone. `t_(3//4)` is the time required for concentration to become `1//4` of original concentration.

For a first order reaction, the ratio of t_(1//2) to t_(3//4) is

Which of the following options correctly represents relationship between t_(7//8) and t_(1//2) where t_(7//8) represents time required for concentration to become (1)/(8) th of original for a reaction of order 'n'?

For the first order reaction AtoB , the time taken to reduce to 1//4 of initial concentration is 10 min. The time required to reduce to 1//16 of initial concentration will be

t_(1//2) is the half of a substance then t_(3//4) is the time in which substance

" For a first order reaction times taken for \(1/4^{th}\) the completion is "20" minutes, the time required for "3/4" the completion is ? "

Show that the time taken to complete 3//4th of the reaction for first order reaction is twice that of the half life period (t_(A//2)) .