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A certain planet's year is 8 times the e...

A certain planet's year is `8` times the earth's year. Find the distance of this planet from the sun if the distance of the earth is `1 AU` from the sun.

Text Solution

Verified by Experts

Let `T_(P), T_(E)` be the period of revolution of planet and earth around the sun. Given,
`T_(P) = 8 T_(E), r_(E) = 1 AU = 1.5 xx 10^(11) m, r_(P) = ?`
As `(T_(P)^(2))/(T_(E)^(2)) = (r_(P)^(3))/(r_(E)^(3)) `or `r_(P) =e_(E)((T_(P))/(T_(E)))^(2//3)`
`= (15 xx 10^(11))(8)^(2//3)`
`= (1.5 xx 10^(11)) xx 4`
`6.0 xx 10^(11) m`
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Knowledge Check

  • The distance of the earth from the sun is about

    A
    1500 million km .
    B
    300 million km
    C
    227 million km
    D
    149 million km.
  • The period of revolution of a planet around the sun is 8 times that of the earth. If the mean distance of that planet from the sun is r, then mean distance of earth from the sun is

    A
    `r//2`
    B
    `2r`
    C
    `r//4`
    D
    `4r`
  • The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun ?

    A
    4
    B
    5
    C
    2
    D
    3
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