If the Earth be at one fourth its present distance from the sun, how many days will be charged in present one year on the surface of earth?

Explanation

Here, `T_(1) = 365` days, `R_(1) = r`
`R_(2) = r//4, T_(2) = ?`
`T_(2) = T_(1) ((R_(2))/(R_(1)))^(3//2)= 365 ((r//4)/(r ))^(3//2)`
`= 365((1)/(4))^(3//2) = 45*6` days
Decrease in the number of days in one year of earth
`= 365 - 45*6 = 319*4` days