At what height from the surface of earth will the value of `g` becomes `40%` from the value at the surface of earth. Take radius of the earth `= 6.4 xx 10^(6) m`.

Explanation

To find the height from the surface of the Earth where the value of \( g \) becomes 40% of its value at the surface, we can follow these steps:

### Step 1: Understand the relationship of \( g \) with height
The acceleration due to gravity \( g \) at a height \( h \) above the Earth's surface is given by the formula:
\[ g' = \frac{g}{(1 + \frac{h}{R})^2} \]
where:
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