A body weighs `64 N` on the surface of Earth. What is the gravitational force on it due to the earth, at a height equal to half the radius of Earth ? Acceleration due to gravity on the surface of Earth is `10 m s^(-2)`.

Explanation

To solve the problem, we need to find the gravitational force acting on a body at a height equal to half the radius of the Earth. We can use the formula for gravitational force at a distance from the center of the Earth.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Weight of the body on the surface of the Earth, \( W = 64 \, \text{N} \)
- Acceleration due to gravity on the surface of the Earth, \( g = 10 \, \text{m/s}^2 \)
- Height \( h = \frac{1}{2} R \), where \( R \) is the radius of the Earth.
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