The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If it is a 2 second's pendulum on earth?

Explanation

Since, `g = GM//R^(2)`, if mass `M` and radius `R` are double, then `g` will reduce to half. Since, time
period `t = 2pi sqrt(l//g)`, i.e., `t prop 1//sqrt(g)`.
Therefore, times period of a pendulum on planet will be `sqrt(2)` times to that on the earth. Thus, the time period of second pendulum of the earth will be `2 sqrt(2)` second on the planet.