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Why the value of acceleration due to gra...

Why the value of acceleration due to gravity is more at the poles than at the equator?

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As `g = (GM)/(R^(2))`, where `M` is the mass and `R` is the radius of earth. The value of `R` is more on equator than at pole. Hence `g` at pole is greater then `g` at equator.
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Knowledge Check

  • SI unit of acceleration due to gravity is

    A
    `ms^(-2)`
    B
    `ms^(-1)`
    C
    N
    D
    `Nkg^(-2)`
  • The value of acceleration due to gravity of earth :

    A
    is the same on equator and poles
    B
    is the least on poles
    C
    is the least on equator
    D
    increase from pole to equator
  • The value of acceleration due to gravity of the earth is

    A
    `98 m//s^2`
    B
    `9.8 m//s^2`
    C
    `0.98 m//s^2`
    D
    `0.098 m//s^2`
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