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A geostationary satellite orbits the Ear...

A geostationary satellite orbits the Earth at a height of nearly `36,000 km` from the surface of earth. What is the potential due to earth's gravity at the site of tthis satllite ? (Take the potential energy at infinity to be zero). Mass of the Earth `= 6.0 xx 10^(24) kg`, radius `= 6400 km, G = 6.67 xx 10^(-11) Nm^(2)//kg^(2)`.

Text Solution

Verified by Experts

Gravitational potential at height `h` from the surface of Earth is
`V = - (GM)/((R + h)) = (-6.67 xx 10^(-11) xx (6 xx 10^(24)))/((6.4 xx 10^(6) + 36 xx 10^(6))) = - 9.4 xx 10^(6) J//kg`
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A geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of the satellite ? Mass of the earth= 6xx10^(24) kg and radius =6400 km.

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A geostationary satellite is orbiting the Earth at a height of 6 R above the surface of Earth, where R is the radius of the Earth. The time period of another satellites is 6 sqrt(2) h . Find its height from the surface of Earth.

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Knowledge Check

  • A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth, where R is the radius of the earth. What is the time period of another satellite orbiting at a height of 2.5 R from the surface of the earth ?

    A
    6.2 hour
    B
    8.48 hour
    C
    9.5 hour
    D
    11.6 hour