Home
Class 11
PHYSICS
Everybody, when free, falls towards the ...

Everybody, when free, falls towards the centre of earth with an acceleration `= g`, which is called acceleration due to gravity. The value of `g` on the surface of earth is, `g = (GM)/(R^(2)) = 9.8 m//s^(2)`. It is a vector, directed always the centre of earth. The value of `g` does not depend upon shape, size or mass of the body. Rether, it depends on mass and size of earth (or planet due to which there is a gravity pull).
Read the above passesge and answer the following questions :
(i) A piece of stone and a feather are dropped together in space from the same height. which one will strike the ground first ? (ii) The mass of a planet is `(1)/(8)th` the mass of earth and its diameter is `(5)/(6)` the diameter of earth. What is the value of 'g' on the surface of this planet.
(iii) What does the concept of free fall imply in day to day life?

Text Solution

Verified by Experts

(i) For both the stone and feather, `g` is same. Therefore, the two hit the ground together.
(ii) Here, `M' = (1)/(8)M, R' = (5)/(6), g' = ?`
`(g')/(g) = (M'//R'^(2))/(M//R^(2)) = (M')/(M) xx ((R )/(R'))^(2) = (1)/(8) xx ((6)/(5))^(2) = (36)/(200)`,
`g' = (36)/(200) xx g = (36)/(200) xx 9.8m//s^(2) = 1.76 m//s^(2)`
(iii) In day to day life, the concept of free fall inplies that unless we hole ourselves against the perverse attractions of the world, we would fall freely to new lows. The acceleration and speed of free fall will be same for anybody and everybody irrespective of their stature.
Promotional Banner

Topper's Solved these Questions

  • GRAVIATION

    PRADEEP|Exercise CURIOSITY QUESTION|1 Videos
  • GRAVIATION

    PRADEEP|Exercise MULTIPLE CHOICE QUESTIONS|116 Videos
  • GRAVIATION

    PRADEEP|Exercise QUESTIONS|14 Videos
  • BEHAVIOUR OF PERFECT GAS & KINETIC THEORY

    PRADEEP|Exercise Assertion - Reason Type questions|14 Videos
  • KINEMATICS

    PRADEEP|Exercise 1 NCERT Comprehension|4 Videos

Similar Questions

Explore conceptually related problems

The value of 'g' on earth surface depends :-

Let g be the acceleration due to gravity on the earth's surface.

The value of 'g' does not depend upon mass of the body, but gravitational pull of earth depends on mass of the body, comment.

Does the value of 'g' depend upon mass of the body?

What is the acceleration due to gravity at a height h ( = radius of the earth) from the surface of the earth ? ltbgt (g=9.8m//s^(2))

At what distance from the centre of the earth, the value of acceleration due to gravity g will be half that on the surface ( R = radius of earth)

At what depth from the surface of the earth, the acceleration due to gravity will be half the value of g on the surface of the earth ?

The mass of a planet and its diameter are three times those of earth's. Then the acceleration due to gravity on the surface of the planet is : (g =9.8 ms^(-2))