The escape velocity of a body from the surface of earth is the minimum velocity of projection of the body from the surface, which would take the body just beyound the gravitational field of earth. Once the body crosses the gravitational field of earth, it will never return to earth on its own. The body is said to have esacped. If `M` is mass of earth and `R` is radius of earth, then esacpe velocity,
`V_(e) = sqrt((2GM)/(R )) = sqrt(2gR)`. The value of `V_(e)` does not depend upon mass of the body.
Read the above passega and answer the following questions :
(i) What is the escape velocity from the surface of earth for a body of mass `2 kg` and for another body of mass `20 kg`? Is the energy required in the two cases same ?
(ii) What value of life do you learn from this study ?

Explanation

To solve the given question, we will break it down into two parts as specified.

### Part (i): Escape Velocity Calculation

1. **Understanding Escape Velocity**:
The escape velocity \( V_e \) from the surface of the Earth is given by the formula:
\[
V_e = \sqrt{\frac{2GM}{R}} = \sqrt{2gR}
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