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Two bodies of masses 100 kg and 1000 kg ...

Two bodies of masses `100 kg` and `1000 kg` are at a distance `1.00 m` apart. Calculate the gravitaional field line joining them. `G = 6.67 xx 10^(-11) N m^(2) kg^(-2)`.

Text Solution

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`I = (Gm_(2))/((r//2)^(2)) - (Gm_(1))/((r//2)^(2)), V = - [(Gm_(1))/((r//2)) + (Gm_(2))/((r//2))]`
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Knowledge Check

  • Two bodies of masses 50 kg and 100 kg are at a distance 1m apart. The intensity of gravitational field at the mid-point of the line joining them is (in joules)

    A
    100G
    B
    150G
    C
    50G
    D
    200G

  • There are two bodies of masses 100 kg and 1000 kg separated by a distance 1m . The intensity of gravitational field at the mid point of the line joining them will be

    A
    `2.4xx10^(-6)N//kg`
    B
    `2.4xx10^(-7)N//kg`
    C
    `2.4xx10^(-8) N//kg`
    D
    `2.4xx10^(-9) N//kg`

  • Two bodies of masses 10 kg and 100 kg are seperated by a distance of 2 m. The gravitational potential at the mid-point of the line joining the two bodies is:

    A
    `-7.3 xx 10^(-7) J//kg`
    B
    `-7.3 xx 10^(-8) J//kg`
    C
    `-7.3 xx 10^(-9) J//kg`
    D
    `-7.3 xx 10^(-6) J//kg`