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A geostationary satellite orbits around ...

A geostationary satellite orbits around the earth in a circular orbit of radius `3600 km`. Then the time period of satellite orbiting `= 2600 km` above the earth's surface `(R_(earth) = 6400 km)` will appoximetely be

A

`1//2 hr`

B

`1 hr`

C

`3 hr`

D

`4 hr`

Text Solution

Verified by Experts

The correct Answer is:
C
Here `r_(1) = 36000 km, r_(2) = 6400 + 2600 = 9000 km`,
`T_(1) = 24 hr T_(2) = ?`
As `T^(2) prop r^(3) :. T_(2) = T_(1) ((r_(2))/(r_(1)))^(3//2)`
`= T_(2) = 24 ((9000)/(36000))^(3//2) = 3h`
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