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A particle hanging from a spring stretch...

A particle hanging from a spring stretches it by 1 cm at earth's surface. How much will the same particle stretch the spring at a place 800 km above the earth's surface/ Radius of the earth=6400 km.

A

`16//50 cm`

B

`16//25 cm`

C

`24//16 cm`

D

`50//16 cm`

Text Solution

Verified by Experts

The correct Answer is:
B
At the surface, `mg = k + 1`
At a certain height, `mg' = k + x`
`:. (x)/(1) = (g')/(g) = (R^(2))/((R + h)^(2))`
`= ((6400)/(6400 + 1600))^(2) = ((4)/(5))^(2) = (16)/(25)`
`x = (16)/(25) xx 1 = (16)/(25) cm`
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