The Young's modulus for steel is `2.0xx10^(11)Nm^(-2)`. If the interatomic spacing for the metal is `2.0 Å`, Find the increases in the interatomic for a force of `10^(9)Nm^(-2)` and the force constant.

Explanation

To solve the problem, we will follow these steps:

### Given Data
1. Young's modulus (Y) for steel: \( Y = 2.0 \times 10^{11} \, \text{N/m}^2 \)
2. Interatomic spacing (L): \( L = 2.0 \, \text{Å} = 2.0 \times 10^{-10} \, \text{m} \)
3. Applied stress: \( \text{Stress} = 10^{9} \, \text{N/m}^2 \)

### Step 1: Understanding Young's Modulus
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