A rectangular film of liquid is extended from `5cm xx 3 cm to 6 cm xx 5 cm`. If the workdone is `3.0 xx 10^(-4)J`. Find the surface tension of liquid.

Explanation

To find the surface tension of the liquid film, we can follow these steps:

### Step 1: Write down the given data
- Initial dimensions of the film: \(5 \, \text{cm} \times 3 \, \text{cm}\)
- Final dimensions of the film: \(6 \, \text{cm} \times 5 \, \text{cm}\)
- Work done: \(W = 3.0 \times 10^{-4} \, \text{J}\)

### Step 2: Calculate the initial and final areas
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