Find the pressure at the tip of a drawing pin on area `0.2 mm` square if it is pushed against a board with a force of 5 kg wt.
(use `g=10m//s^(2))`

Explanation

Here, `A = 0.2 mm sq`
`=0.2 xx 0.2 sq mm = 0.04 xx 10^(-6)m^(2)`
`F=5 kg wt = 5 xx 10 N`
Pressure ,`P=F/A = (5 xx 10)/(0.04 xx 10^(-6))=1.25 xx 10^(9) Pa`.