The average mass that can be lifted by a hydraulic press is 100kg. If the radius of the larger piston is six times that of a smaller poston. What is the minimum force (in kg wt) that must be applieed? Use `g=10ms^(-2)`.

Explanation

Here `F_(2) = 100 kgf = 100 xx 10 N`
`A_(2) = 6 A_(1), F_(1)=?`
As `(F_1)/(A_1) = (F_1)/(A_2) or F_(1) = (A_1)/(A_2) xx f_(2) = (A_(1) xx 100 xx 10)/(6 A_(1))`
`=(100 xx 10 )/(6) N = (100 xx 10)/(6xx10) kgf`
`=16.67 kgf`.