The area of smaller piston of a hydraulic pressure is `2cm` square and that of larger piston is 20 cm square. How much weight can be raised on the larger piston when a force 200kg f is exerted on the smaller piston? `g=10m//s^(2)`

Explanation

Here` A_(1)=2 cm sq = 2 xx 2 sq cm`
`A_(2) = 20 xx 20 sq cm = 400 xx 10^(-4)m^(2)`
`F_(1) = 200 kg f=200 xx 10N , F_(2)=?`
`F_(2) =(A_2)/(A_1) F_(1) = ((400 xx 10^(-4)) xx (200 xx 10))/(4 xx 10^(-4))`
`= 2 xx 10^(5) N = 2 xx 10^(4) kg f`.