A piece of pure gold of density `19.3 g cm^(-3)` is suspected to be hollow inside. It weighs 38.250 g in air and 33.865 g in water. Calculate the volume of the hollow portion of the gold, if any:

Explanation

To find the volume of the hollow portion of the gold piece, we can follow these steps:

### Step 1: Calculate the volume of the gold piece in air
We know the mass of the gold piece in air is 38.250 g and the density of pure gold is 19.3 g/cm³. The volume can be calculated using the formula:

\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
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