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A liquid Flows through a pipe 2.0 mm rad...

A liquid Flows through a pipe 2.0 mm radius and 20 cm length under a pressure `10^(3)" dyne "cm^(-2)`. Determine the rate of flow and the speed of the liquid coming out of the tube. The coefficient of viscosity of the liquid is 1.25 centipoise.

Text Solution

Verified by Experts

Here, `r = 2.0 mm = 0.2 cm , l=20 cm , p=10^(3)" dyne "cm^(-2) , eta = 1.25 " centipoise "= 0.0125" poise"`
Rate of flow of liquid through the tube is
`V= (pi p r^(4))/(8 eta l) = ((3.142)xx10^(3)xx (0.2)^(4))/(8 xx 0.0125 xx 20) = 2.51 cm^(3) s^(-1)`
Speed of liquid, `upsilon = V/(pi r^(2)) = (2.51)/(3.142 xx (0.2)^(2))= 20 cm s^(-1)`.
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