The flow rate of water from a tap of diameter 1.25 cm is `0.48 L//mi n`. The coefficient of viscosity of water is `10^(-3) Pa-s`. After sometime, the flow rate is increased to `3L//mi n`. Characterise the flow for both the flow rates.

Explanation

To characterize the flow of water from a tap at two different flow rates, we will calculate the Reynolds number (Re) for each case. The Reynolds number helps us determine whether the flow is laminar or turbulent.

### Given Data:
- Diameter of the tap (d) = 1.25 cm = 0.0125 m
- Coefficient of viscosity of water (μ) = \(10^{-3}\) Pa·s
- Flow rate 1 (Q1) = 0.48 L/min = \(0.48 \times 10^{-3} \, \text{m}^3/\text{min}\)
- Flow rate 2 (Q2) = 3 L/min = \(3 \times 10^{-3} \, \text{m}^3/\text{min}\)

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