A liquid is flowing through a horizontal pipe line of varying cross - section .At a certin point the diameter of the pipe is `6cm` and the velocityof flow of liquid is`2.0cm s^(-1)` Calculate the velocity of flow at another point where the diameter is `1.5 cm.

Explanation

Here, `D_(1) = 6 cm , upsilon_(1) = 2.0 cm s^(-1)`,
`upsilon_(2) = ?, D_(2) = 1.5 cm`
From equation of continuty
`(pi D_(1)^(2))/(4) upsilon_(1) = (pi D_(2)^(2))/(4) upsilon_(2) or upsilon_(2) = upsilon_(2) (D_(1)^(2))/(D_(2)^(2))`
`upsilon_(2) = 2.0 xx (6/1.5)^(2) = 32 cm//s`.