Water at a pressure of `4xx 10^(4) Nm^(-2)` flows at `2 ms^(-1)` through a horizontal pope of `0.02 m^(2)`. What is the pressure in the smaller cross-section of the pipe?

Explanation

To solve the problem of finding the pressure in the smaller cross-section of the pipe, we can use the principle of conservation of mass (continuity equation) and Bernoulli's equation.

### Step-by-Step Solution:

1. **Identify Given Data:**
- Initial pressure \( P_1 = 4 \times 10^4 \, \text{N/m}^2 \)
- Initial velocity \( V_1 = 2 \, \text{m/s} \)
- Cross-sectional area of the larger section \( A_1 = 0.02 \, \text{m}^2 \)
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