Calculate the minimum pressure required to force the blood from the heart to the top of the head (vercical distance = 40 cm). Assume that the denisity of blood to be `1.04 g cm^(3)`. Friction is to be neglected.

Explanation

Here, `H_(2)-h_(1) = 40 cm,`
` rho = 1.04 g cm^(-3)`
Ac cording to Bernoulli's Theorem
`P_(1) + rho gh_(1) +1/2 rho upsilon_(1)^(2) = P_(2) + rho gh_(2) +1/2 rho upsilon_(2)^(2)`
or `P_(1) - P_(2) =rho g (h_(2)-h_(1)) +1/2 rho (upsilon_(2)^(2) - upsilon_(1)^(2) )`
Let `upsilon_(2) = upsilon_(1)` then, `P_(1)-P_(2) = rho g (h_(2)-h_(1))`
`= 1.04 xx 980 xx (40) = 4.1 xx 10^(4) dyn e//cm^(2)`.