A small sphere of mass 'm' is dropped from a great height. After it has fallen 100m, it has attained its terminal velocity and continue to fall at that speed. The workdone by air friction against the sphere during 100m fall is `W_(1)` and during next 100m fall is `W_(2)` , then compare `W_(1) and W_(2)`.

Explanation

Since the viscous force `F= 6 pi eta r upsilon` i.e., `F prop upsilon` so the viscous force in the first 100m will be smaller than the next 100m fall. Hence work done `W_(1)` will be less than that of `W_(2)`, i.e., `W_(1) lt W_(2)`.