There are two holes, each of cross-sectional area a, on the opposite side of a wide rectangular tank containing a liquid of density`rho`. When the liquid flows out of the holes, find the net force on the tank. Given h is the vertical distance between two holes.

Explanation

When liquid flows out of the holes from the tank of area of cross-section a with velocity `upsilon` then force on the tank is equal to rate of change of linear momentum i.ei `F = (a upsilon rho) = a upsilon^(2) rho`
Net force on tank =` a rho (upsilon_(2)^(2)-upsilon_(1)^(2))`
`= a rho [2 g (h+x)-2gx]`
`=2 a rho gh`
` [ :' upsilon_(1) = sqrt(2 gx) and upsilon_(2) = sqrt(2 g (x+h)) ]`.