Calculate the difference between the two principal specific heats of 2 gram of hilium gas at S.T.P. Given atomic weight of hilium = 4 and `J =4.186 J cal^(-1) ` and `R = 8.31 J mol^(-1)K^(-1)`.

Explanation

No. of moles in 2 g of helium
`n = 2/4 = 1/2`
Gas constant for 2 g helium , `R' = n R = 1/2 R`
`:. C_(p) = C_(upsilon) = (R')/(J) = (R )/(3J) = 8.31/(2 xx 4.186)`
`=0.993 cal g^(-1) K^(-1)`.