A load of 981 N is suspended from a steel wire of radius 1 mm. what is the maximum angle through which the wire with the load can be deflected so that it does not break when the load passes through the equilibrium poision? Breaking stress is `7.85 xx 10^(8)Nm^(-2)`.

Explanation

To solve the problem step by step, we will follow these procedures:

### Step 1: Identify the given values
- Load (weight) \( W = 981 \, \text{N} \)
- Radius of the wire \( r = 1 \, \text{mm} = 1 \times 10^{-3} \, \text{m} \)
- Breaking stress \( \sigma_{\text{break}} = 7.85 \times 10^{8} \, \text{N/m}^2 \)

### Step 2: Calculate the cross-sectional area of the wire
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