A piece of copper having a rectangular cross section of `15.2 xx 19.1 mm` is pulled in tension with 45,500N, force producing only elastic deformation. Calculate the resulting strain. Shear modulus of elasticity of copper is `42 xx 10^(9)Nm^(-2)`.

Explanation

To solve the problem, we need to calculate the strain produced in the copper piece when it is subjected to a tensile force. We will follow these steps:

### Step 1: Calculate the Cross-Sectional Area
The cross-sectional area \( A \) of the rectangular piece of copper can be calculated using the formula:
\[ A = \text{width} \times \text{height} \]
Given the dimensions:
...