A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1m, is whirled in a vertical circle with an angular velocity of `2 rev.//s` at the bottom of the circle. The cross-sectional area of the wire is `0.065 cm^(2)` . Calculate the elongation of the wire when the mass is at the lowest point of its path `Y_(steel) = 2 xx 10^(11) Nm^(-2)`.

Explanation

To solve the problem of calculating the elongation of the steel wire when a 14.5 kg mass is whirled in a vertical circle at the lowest point, we will follow these steps:

### Step 1: Calculate the gravitational force acting on the mass
The gravitational force (weight) can be calculated using the formula:
\[ F_g = m \cdot g \]
where:
- \( m = 14.5 \, \text{kg} \) (mass)
- \( g = 9.8 \, \text{m/s}^2 \) (acceleration due to gravity)
...