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What is the density of ocean water at a ...

What is the density of ocean water at a depth, where the pressure is 80.0 atm, given that its density at the surface is `1.03 xx 10^(3) kg m^(-3)`? Compressibilty of water `= 45.8 xx 10^(-11) Pa^(-1)`. Given 1 atm. =`1.013 xx 10^(5) Pa`.

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To find the density of ocean water at a depth where the pressure is 80.0 atm, we can use the concept of compressibility and the relationship between pressure, volume, and density. Here’s the step-by-step solution: ### Step 1: Convert pressure from atm to Pa Given: - Pressure at depth \( P = 80.0 \, \text{atm} \) - \( 1 \, \text{atm} = 1.013 \times 10^5 \, \text{Pa} \) Calculate the pressure in Pascals: ...
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Knowledge Check

  • At a depth of 500 m in an ocean what is the absolute pressure? Given that the density of seawater is 1.03xx10^3 kg m^(-3) and g=10m/s^2

    A
    40 atm
    B
    52 atm
    C
    32 atm
    D
    62 atm
  • Estimate the change in the density of water in ocean at a depth fo 500m below the surface. The density of water at the surface = 1030 kgm^(-3) and the bulk modulus of water = 2.2xx10^(9) Nm^(-2)

    A
    `2.363 kg//m^(3)`
    B
    `1.363 kg//m^(3)`
    C
    `4.363 kg//m^(3)`
    D
    `3.363 kg//m^(3)`
  • At what depth in fresh water the pressure on a diver is one atmosphere ? [Density of water = 10^(3)kg m^(-3), Normal pressure =10^(5)Pa, g =10 ms ^(-2)]

    A
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    B
    `10.5` m
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