What is the density of ocean water at a depth, where the pressure is 80.0 atm, given that its density at the surface is `1.03 xx 10^(3) kg m^(-3)`? Compressibilty of water `= 45.8 xx 10^(-11) Pa^(-1)`. Given 1 atm. =`1.013 xx 10^(5) Pa`.

Explanation

To find the density of ocean water at a depth where the pressure is 80.0 atm, we can use the concept of compressibility and the relationship between pressure, volume, and density. Here’s the step-by-step solution:

### Step 1: Convert pressure from atm to Pa
Given:
- Pressure at depth \( P = 80.0 \, \text{atm} \)
- \( 1 \, \text{atm} = 1.013 \times 10^5 \, \text{Pa} \)

Calculate the pressure in Pascals:
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