How much should the pressure on a litre of water be changed to compress it by 0.10%? Bull modulus of elasticity of water = `2.2 xx 10^(9) Nm^(-2)`.

Explanation

Here, `V = 1 litre = 10^(-3)m^(3) , (Delta V)/(V) = 0.10//100 = 10^(-3)`
`B = (pV)/(Delta V) or p=B(Delta V)/(V) = (2.2 xx 10^(9)) xx 10^(-3) = 2.2 xx 10^(6) Pa`.