A tank with a square base of area `1.0m^(2)` is divided by a vertical parition in the middle. The bottom of the partition has a small hinged door of area `20cm^(2)`. The tank is filled with water and an acid (of relative density 1.7) in the other, both to a height of `4.0m`. Compute to force necessary the force nec cessary to keep the door closed.

Explanation

To find the force necessary to keep the door closed in the tank, we will follow these steps:

### Step 1: Determine the density of water and acid
- The density of water (ρ_w) is given as \(1000 \, \text{kg/m}^3\).
- The relative density of acid is \(1.7\), so the density of acid (ρ_a) can be calculated as:
\[ \rho_a = 1.7 \times \rho_w = 1.7 \times 1000 \, \text{kg/m}^3 = 1700 \, \text{kg/m}^3 \]
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