A steel rod `(Y = 2.0xx10^(11) N//m^(2)` and `alpha = 10^(-50) .^(0)C^(-1)`) of length `1m` and area of cross-section `1cm^(2)` is heated from `0^(@)C` to `200^(@)C` without being allowed to extended or bend. Then the tension produced in the rod is

Explanation

Here, `Y = 2.0 xx 10^(11) N//m^2 , alpha = 10^(-5) .^@C^(-1) , l = 1 m`
`Delta T = 200 - 0 = 200^@C, A =1cm^2 = 10^(-4)m^2`
Tension = thermal stress `xx` area of cross = section `= Y alpha Delta T xx A = (2xx10^(11)) xx 10^(-5) xx 200 xx 10^(-4)` `=4xx10^4 N`