Two mercury droplets of radii 0.1 cm and 0.2 cm collapse into one single drop. What amount of energy is released? The surface tension of mercury `T = 435. 5xx10^(-3) Nm^(-1)`

Explanation

To find the amount of energy released when two mercury droplets of radii 0.1 cm and 0.2 cm collapse into a single drop, we will follow these steps:

### Step 1: Calculate the Surface Energy of the Initial Droplets
The surface energy (Q) of a droplet is given by the formula:
\[ Q = T \times A \]
where \( T \) is the surface tension and \( A \) is the surface area of the droplet.

The surface area \( A \) of a sphere is given by:
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