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Specific heat of water is 1 cal g^(-1) ....

Specific heat of water is 1 cal `g^(-1) .^(@)C^(-1)`

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The heater coil of an elecric kettle is rated at 2000W,200V, How much time will in take is rasing the temperature of 1 litres of water from 20^(@)C to 100^(@)C . Assuming that only 80% of the total heat energy produced by the heater coil is used in raising the temperature of water. Density of water heater coil is used in raising the temperture of water. density of water = 1g cm^(-3) and specific heat of water = 1 "cal" g^(-1) .^(@)C^(-1) .

The heater coil of an elecric kettle is rated at 2000W,200V, How much time will in take is rasing the temperature of 1 litres of water from 20^(@)C to 100^(@)C . Assuming that only 80% of the total heat energy produced by the heater coil is used in raising the temperature of water. Density of water heater coil is used in raising the temperture of water. density of water = 1g cm^(-3) and specific heat of water = 1 "cal" g^(-1) .^(@)C^(-1) .

Stream at 100^(@)C is passed into 20 g of water at 10^(@)C . When water acquires a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of steam =540 cal g^(-1) ]

Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

A refrigeratior converts 50 gram of water at 15^(@)C intoice at 0^(@)C in one hour. Calculate the quantity of heat removed per minute. Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of ice =80 cal g^(-1)

A 30V storage battery is being charged by 120V d.c. supply. A resistor has been connected in series with the battery to limit the charging current to 10A. Find the rate at which energy is dissipated in the resistor. If the total heat produced could be made available for heating water, how long would it take to bring 1 kg of water from 10^(@)C to the boiling point? Specific heat of water =1 "cal" g^(-1).^(@)C^(-1) and from 15^(@)C to the boiling point ? Specific heat of water =1 cal g^(-1).^(@)C^(-1) and 1 cal=4.2J

A calorimeter of water equivalent 20 g contains 180 g of water at 25^(@)C . 'm' grams of steam at 100^(@)C is mixed in it till the temperature of the mixture is 31^(@)C . The value of m is close to (Laten heat of water = 540 cal g^(-1) , specific heat of water = 1 cal g^(-1) ""^(@)C^(-1))