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Figure shows the volume versus temperatu...

Figure shows the volume versus temperature graph for the same mass of a gas (assumed ideal) corresponding to two different pressure `P_(1) and P_(2)`. Then

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For a perfect gas, `PV=nRT :. V=(nR)/(P)T`
slope of V-T graph with T axis = `(nR)/P`
For given amount of gas, slope `prop1/P`
Hence `P_(1) gt P_(2)`
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