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One mole of a monoatomic gas is mixed wi...

One mole of a monoatomic gas is mixed with three moles of a diatomic gas. What is the molecular specific heat of mixture at constant volume? `R=8.31 J mol^(-1) K^(-1)`.

Text Solution

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For monoatomic gas, `C_(v)=3/2R , n=1`
For diatomic gas, `C'_(v)=5/2R,n'=3`
From conservations of energy, we can write for the mixture.
`C"_(v)=(n(C_(v))+n'(C_(v)))/(n+n')=(1xx3/2R+3xx5/2R)/(1+3)`
`C"_(v)=(9R)/4= 9/4xx8.31= 18.7 J mol e^(-1)K^(-1)`
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