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A person of mass 60 Kg wants to lose 5 k...

A person of mass `60 Kg` wants to lose `5 kg` by going up and down a `10 m` high stairs. Assume he burns twice as much fat while going up than coming down. If `1 kg` of fat is burnt on expending `7000 kilo` calories, how many times must be go up and down to reduce his weight by `5kg`?

Text Solution

Verified by Experts

Here, `m= 60 kg, g= 10 m//s^(2), h= 10m`
In going up and down once, number of kilocalories burnt `= (mgh+mgh//2)`
`3/2xx(60xx10xx10)/(4.2xx1000)= 6/(2.8) K cal`.
Total no. of kilocalories to be burnt for losing `5Kg` of weight `= 5xx7000= 35000 cal`.
`:.` Number of times the person has to go up and down the stairs `= (35000)/(6//2.8)= (35xx2.8)/6xx10^(3)`
`= 16.3xx10^(3)` times.
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