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If the co-efficient of performance of a refrigerator is 5 and operates at the room temperature `(27^(@)C)`, find the temperature indide the refrigerator.

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Here, `COP = beta = 5, T_(1) = 270^(@)C = (27+273)K = 300K , T_(2) = ?`
As `beta= (T_(2))/(T_(1)-T_(2)) :. 5= (T_(2))/(300-T_(2)) , T_(2)= 250K = (250-273)^(@)C = -23^(@)C`
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