Starting with the same initial conditions, an ideal gas expands from volume `V_1 to V_2` in three different ways. The work done by the gas is W_1 if the process is purely isothermal, `W_2`if purely isobaric and `W_3` if purely adiabatic. Then

Options

A. `W_(2)gtW_(1)gtW_(3)`
B. `W_(2)gtW_(3)gtW_(1)`
C. `W_(1)gtW_(2)gtW_(3)`
D. `W_(1)=W_(2)=W_(3)`

Answer

A

Explanation

As is known,work done= area under `P-V` curve. From (figure), we find that

`A_(2)gtA_(1)gtA_(3) :. W_(2)gtW_(1)gtW_(3)`