A solid body of constant heat capacity `1J//^@C` is being heated by keeping it contact with reservoirs in two ways:
(i) Sequentially keeping in contact with 2 reservoirs such that each reservoir supplies same amount of heat.
(ii) Sequentially keeping in contact with 8 reservoir such that each reservoir supplies same amount of heat.
In both the cases body is brought from initial temperature `100^C` to final temperature `200^@C`. Entropy change of the body in the tow cases respectively is :

Options

A. In 2,4, in 2
B. In 2, In 2
C. In 2, 2 In 2
D. 2 In 2, 8 In 2

Answer

B

Explanation

Entropy `DeltaS= (DeltaQ)/T=(msDeltaT)/T`
Change in entropy,
`DeltaS'= ms int_(T_(1))^(T_(2))(DeltaT)/T= "ms log"_(e)(T_(2))/(T_(1))`
`=1xx"log"_(e)(200)/(100)= In2`
Since entropy is state function, therefore change in entropy in both the process should be the same. Hence the correct option is (b).