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In a given process on an ideal gas, dW=0...

In a given process on an ideal gas, `dW=0 and dQlt0.` Then for the gas

A

temperature will decrease

B

volume will increase

C

pressure will remain constant

D

temperature will increase

Text Solution

Verified by Experts

The correct Answer is:
A
From first law of thermodynamics,
`dQ= dU+dW`
`dQ=dU, as dW=0`
As `dQlt0, therfore, dUlt0`
`:.` temperature will decrease
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