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When a system is taken from state i to state f along the path iaf, it is found that `Q=50 cal and W=20 cal`. Along the path ibf `Q=36cal`. W along the path ibf is

A

`14 cal.`

B

`6 cal.`

C

`16 cal.`

D

`66 cal.`

Text Solution

Verified by Experts

The correct Answer is:
B
Along the path `iaf`,
Increase in internal energy,
`U_(1)=Q_(1)-W_(1)= 50-20= 30Cal.`
Along the path `ibf`
Increase in inernal energy,
`U_(2)=Q_(2)-W_(2)`
`U_(2)= 36-W`
As `U_(2)=U_(1) :. 36-W= 30`
`W= 36-30= 6 Cal`
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