An ideal gas heat engine operates in Carnot cycle between `227^(@)C` and `127^(@)C`. It absorbs `6 x 10^(4) cals` of heat at higher temperature. Amount of heat converted to work is

Options

A. `4.8xx10^(4)cals`
B. `2.4xx10^(4)cals`
C. `1.2xx10^(4)cals`
D. `6xx10^(4)cals`

Answer

C

Explanation

Here, `T_(1)= 227^(@)C= 227+273= 500K`
`T_(2)= 127^(@)C= 127+273= 400K`
`Q_(1)= 6xx10^(4)cals. W=?`
As `(Q_(2))/(Q_(1))= (T_(2))/(T_(1))`
`:. Q_(2)= (T_(2))/(T_(1))xxQ_(1)= (400)/(500)xx6xx10^(4)`
`=4.8xx10^(4)cals`
`W= Q_(1)-Q_(2)= 6xx10^(4)-4.8xx10^(4)`
`=1.2xx10^(4)cals.`