An ideal gas heat engine operates in a Carnot cycle between `227^(@)C and 127^(@)C`. It absorbs `6K cal.` of heat at higher temperature. The amount of heat in `k cal` rejected to sink is

Options

A. `4.8`
B. `2.4`
C. `1.2
D. `6.0`

Answer

A

Explanation

Here, `T_(1)= 227^(@)C = 227+ 273= 500K`
`T_(2)= 127^(@)C= 127+273= 400K`
`Q_(1)= 6k cal Q_(2)=?`
`(Q_(2))/(Q_(1))= (T_(2))/(T_(1))= (400)/(500)= 4/5`
`Q_(2)= 4/5Q_(1)= 4/5xx6 kcal= 4.8Kcal`