A Carnot engine absorbs `6xx10^(5)cal`. At `227^(@)C`. Heat rejected to the sink at `127^(@)C` is

Options

A. `6xx10^(5)cal`
B. `4.8xx10^(5)cal`
C. `4xx10^(5)cal`
D. `5xx10^(5)cal`

Answer

B

Explanation

Here, `Q_(1)= 6xx10^(5)cal`
`T_(1)= 227^(@)C= 227+273= 500K`
`Q_(2)=?= 127^(@)C= 127+273= 400K`
`(Q_(2))/(Q_(1))=(T_(2))/(T_(1))`
`Q_(2)=(T_(2))/(T_(1))Q_(1)= (400)/(500)xx6xx10^(5)cal`
`=4.8xx10^(5)cal`