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Work done //cycle by the engine in the a...

Work done //cycle by the engine in the above questions is

A

`5.04xx10^(5) J`

B

`5.04xx10^(5)cal`

C

`4.8xx10^(5)cal`

D

`4.8xx10^(5)J`

Text Solution

Verified by Experts

The correct Answer is:
A

`W=Q_(1)-Q_(2)= 6xx10^(5)-4.8xx10^(5)`
`=1.2xx10^(5)cal`
`= 1.2xx10^(5)xx4.2J`
`=5.04xx10^(5)J`
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Carnot engine is an ideal heat engine, which converts heat energy into mechanical energy. Efficiency of Carnot engine is given by eta =1 - (T_2 // T_1) , where T_1 is temperature of source and T_1 , is temperature of sink. If Q_1 is the amount of heat absorbed/cycle from the source, Q_2 is the amount of heat rejected/cycle to the sink and W is the amount of useful work done/cycle, then W= Q_1 -Q_2 and (Q_2)/(Q_1) = (T_2)/(T_1) Work done/cycle by the engine in the above question is. if source and sink temperature respectively 227 and 127 . heat absorbed by engine is given 6 .

Efficiency of the engine in the above questions is

Carnot engine is an ideal heat engine, which converts heat energy into mechanical energy. Efficiency of Carnot engine is given by eta =1 - (T_2 // T_1) , where T_1 is temperature of source and T_1 , is temperature of sink. If Q_1 is the amount of heat absorbed/cycle from the source, Q_2 is the amount of heat rejected/cycle to the sink and W is the amount of useful work done/cycle, then W= Q_1 -Q_2 and (Q_2)/(Q_1) = (T_2)/(T_1) Efficiency of the engine in the above question is .if source and sink temperature respectively 227 and 127 .

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  16. A Carnot engine absorbs 6xx10^(5)cal. At 227^(@)C. Heat rejected to th...

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  17. Work done //cycle by the engine in the above questions is

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  18. Efficiency of the engine in the above questions is

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  19. At what temperature should the sink be maintained to increase the effi...

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  20. What should be the temperature of the source to increases the efficien...

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